Mathematics RU

Practice · Chapter 11

Systems of two equations

Systems of two linear equations: substitution, elimination, how many solutions a system has — and word problems about tickets, boats and mixtures.

How to solve it

To solve a system is to find a pair $(x,\ y)$ that fits both equations at once. Both methods do the same thing: get rid of one unknown, so that an ordinary equation in one unknown is left.

Step by step

  1. Bring both equations to the form “unknowns on the left, a number on the right”.
  2. Substitution: express one unknown from the equation where it is easy (coefficient $\pm 1$) and put it into the other.
  3. Elimination: multiply the equations by numbers that make the coefficients of one unknown opposite, then add — it disappears.
  4. Find the other unknown by substituting the first into either equation. Check the pair in both.
  5. If both unknowns disappear: $0 = 0$ means infinitely many solutions, $0 = 7$ means none.
The coefficients of $x$. The coefficients of $y$. The determinant: if $\Delta \ne 0$ there is exactly one solution; if $\Delta = 0$ there are none or infinitely many (the lines are parallel or the same). Example: $\begin{cases} 2x - 3y = -12 \\ 6x - 9y = -36 \end{cases}$ — the second equation is the first times $3$: the lines coincide, there are infinitely many solutions.

Common mistakes

  • Substituting the expressed unknown back into the same equation: that gives $0 = 0$ and looks like infinitely many solutions.
  • Multiplying an equation by a number and forgetting the right-hand side.
  • Finding $x$ and forgetting $y$: the answer of a system is always a pair.
  • In river problems mixing up the speeds: downstream it is $x + y$, upstream $x - y$.

Example