Mathematics RU

Practice · Chapter 54

Measure and Lebesgue integrals

Lebesgue measure is length for complicated sets: countable sets and rational points, Cantor's dust, and the Lebesgue integral of a function defined differently on rationals and irrationals.

How to solve it

Lebesgue measure generalizes length: an interval's measure is its length, and a union of disjoint pieces has the sum of their measures. Every countable set — all the rationals, for example — has measure zero: each point can be covered by an arbitrarily short interval. So the Lebesgue integral does not care what happens on a set of measure zero.

Step by step

  1. Split the set into simple pieces — intervals, points, countable sets — and add the measures. Count overlaps once.
  2. A countable set (finite, the naturals, the rationals, the rational points of an interval) has measure $0$.
  3. A “dust” construction: each step keeps the same share. After $n$ steps the measure is that share to the power $n$.
  4. The Lebesgue integral: if a function equals an ordinary one almost everywhere (except on a set of measure zero), the integral is the ordinary integral of that one.
The rational points of an interval: a countable set of measure zero. Equal everywhere except on a set of measure zero. Example: $f = 3x + 5$ at the irrational points of $[1,\ 3]$ and $5$ at the rational ones. Almost everywhere $f = 3x + 5$, so $\int f\,d\mu = \int_1^3 (3x + 5)\,dx = 22$.

Common mistakes

  • Thinking the rational points of an interval are “many” because they are everywhere, and giving them positive measure.
  • In a dust construction removing parts only at the first step: the remaining share multiplies at every step.
  • Counting the function's values at the rational points in a Lebesgue integral.
  • Adding the measures of overlapping sets without removing the common part.

Example