Mathematics RU

Practice · Chapter 25

Computing limits

Limits by substitution and cancelling, limits of fractions at infinity and the limit of sin t / t. The forms 0/0 and ∞/∞ — and how to get rid of them.

How to solve it

A limit is the value a function approaches as $x$ approaches a point. If substitution gives a number, that is the answer. If it gives $\frac{0}{0}$ or $\frac{\infty}{\infty}$, the expression has to be transformed — most often by cancelling a common factor or dividing by the highest power.

Step by step

  1. Substitute the point. A number — done.
  2. $\frac{0}{0}$ in a fraction of polynomials: both the top and the bottom are divisible by $x - a$. Factor, cancel, substitute again.
  3. $x \to \infty$: divide the top and the bottom by the highest power of $x$. Terms like $\frac{c}{x^k}$ go to zero, and the ratio of the leading coefficients is left.
  4. With a sine: fit the expression to $\frac{\sin t}{t} \to 1$ by multiplying and dividing by the right number.
The same expression under the sine and in the denominator, going to zero. Example: $\frac{\sin 3x}{5x} = \frac{3}{5} \cdot \frac{\sin 3x}{3x} \to \frac{3}{5}$.

Common mistakes

  • Seeing $\frac{0}{0}$ and answering “$0$” or “no limit”. It is a signal to transform the expression, not an answer.
  • “Cancelling the sine” in $\frac{\sin 3x}{5x}$ to get $\frac{3}{5}$ — right by accident; the honest way is the special limit with a factor of $3$.
  • At infinity comparing the constant terms instead of the highest powers.
  • Cancelling $x - a$ and forgetting to substitute the point again.

Example