Mathematics RU

Practice · Chapter 58

Angle excess and defect

On a sphere the angles of a triangle add up to more than 180°, on the hyperbolic plane to less. Find the area of a triangle or a polygon from its angles.

How to solve it

On the plane a triangle's angles always add up to $180^\circ$. On a sphere they add up to more, and the excess is the triangle's area divided by $R^2$. On the hyperbolic plane they add up to less, and the defect gives the area. The bigger the figure, the stronger the difference from the plane.

Step by step

  1. Add the angles and convert the sum to radians ($180^\circ = \pi$).
  2. A sphere: the excess $\varepsilon = (\alpha + \beta + \gamma) - \pi$. For an $n$-gon, the angle sum minus $(n - 2)\pi$.
  3. The hyperbolic plane: the defect $\delta = \pi - (\alpha + \beta + \gamma)$; for an $n$-gon, $(n - 2)\pi$ minus the angle sum.
  4. The area: $S = R^2 \cdot \varepsilon$ on a sphere and $S = R^2 \cdot \delta$ on the hyperbolic plane of curvature $-\frac{1}{R^2}$.
The radius of the sphere (on the hyperbolic plane, the radius of curvature). The angle sum in radians. The angle sum of a flat triangle. On the hyperbolic plane it is the other way: $\pi$ minus the sum. Example: angles $30^\circ$, $75^\circ$, $120^\circ$ on a sphere of $R = 6$: the sum is $225^\circ$, the excess $45^\circ = \frac{\pi}{4}$, the area $36 \cdot \frac{\pi}{4} = 9\pi$.

Common mistakes

  • Using the excess in degrees instead of radians.
  • Subtracting $\pi$ for a polygon instead of $(n - 2)\pi$.
  • Getting the sign wrong: on the hyperbolic plane the excess is negative, and the area is the defect, positive.
  • Forgetting to multiply by $R^2$.

Example