Mathematics RU

Exams · Russian state exam, profile level

No. 18 A problem with a parameter

The equation has a letter a in it. Find every a for which the equation has exactly two roots.

How to solve it

Equations with a parameter

An equation with a parameter has a letter besides $x$, usually $a$: $x^2 - 2ax + 9 = 0$. Its value is not given, and you need every value of $a$ for which the equation behaves as asked, for example has exactly two roots. The answer is not a number but a set of values of $a$.

Step by step

  1. See where the parameter sits. If it is in the coefficient of $x^2$, deal separately with the case where that coefficient is zero: the equation becomes linear.
  2. A quadratic equation has two roots exactly when its discriminant is positive. Write $D$ in terms of $a$.
  3. Solve the inequality $D > 0$ for $a$.
  4. Write the answer as intervals of $a$.
The coefficient of $x$. The parameter may sit here. The constant term. The parameter may sit here as well. Example: $x^2 - 2ax + 9 = 0$. Here $D = 4a^2 - 36 > 0$, so $a^2 > 9$: $a < -3$ or $a > 3$. Answer: $(-\infty, -3) \cup (3, +\infty)$.

Common mistakes

  • Solving $D \ge 0$ instead of $D > 0$. At $D = 0$ there is only one root.
  • Getting only $a > 3$ out of $a^2 > 9$ and losing the negative values.
  • Skipping the case where the parameter makes the coefficient of $x^2$ zero.

Example